Question 631162
{{{(3x^-2y^3)^3/3x^4y^-1}}}
Use properties:
{{{(a^n)^k=a^(n*k)}}}
{{{(ab)^n=a^n*b^n}}}
{{{a^n/a^k=a^(n-k)}}}
{{{a^(-n)=1/a^n}}}
.
{{{(3x^-2y^3)^3/3x^4y^-1=3^3x^-6y^9/3x^4y^-1=3^(3-1)x^(-6-4)y^(9-(-1))=3^2x^-10y^10=9y^10/x^10}}}