Question 631129
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Hi,
Re: TY 
Am not set-up for private-pay tutoring. 
Recommend checking the list of Tutors, a number of them are.
In general: If P(happening) = 1/n ,  ODDS against would be: (n-1) to 1.
for ex: p = 1/8, then odds against would be 7 to 1.  
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p(man)= 1/2 & q(women)= 1/2 or .5
nCx = {{{n!/(x!(n-x)!)}}}
If the are 13 job posiitons open, and all other things being equal, what is P(x= 13)
  P(x = 13) = {{{13C13(.5)^13(.05)^0}}}