<PRE><B>Question 630978</B>
What is the standard form equation of the line passing through (3, –2) with a slope of 3/5


We use the formula:


y - y1 = m(x - x1)

y - (-2) = 3/5(x - 3)

y - (-2) = y + 2

Now we have:

y + 2 = 3/5(x - 3)

Cross multiply:

5(y + 2) = 3(x - 3)

5 * y = 5y

5 * 2 = 10

3 * x = 3x

3 * -3 = -9

Therefore:

5y + 10 = 3x - 9

Subtract 10 from each side of the equation.

5y + 10 - 10 = 3x - 9 - 10

Combine like terms:

10 - 10 = 0

-9 - 19 = -19

Therefore:

5y = 3x - 19

Divide each item by 5

5y/5 = 3x/5 - 19/5

y = 3x/5 - 19/5


The Answer:

y = 3x/5 - 19/5




Lennox Obuong
Algebra Student
Email: obuong3@aol.com</PRE>