Question 630895
Let theta be an angle in quadrant 2 such that cos= -3/5 . 
Find the exact values of csc theta and cot theta .
**
cos=-3/5=adjacent side/hypotenuse
opposite side must be =4, (3-4-5) right triangle
csc=hypotenuse/opposite side=5/4
cot=adjacent side/opposite side=-3/4
csc theta=5/4
cot theta=-3/4