Question 630984
Given: A rectangular field  

Length of the field is 18 m longer than the width (L = W + 18)

Perimeter (P) = 276 m


Determine: The dimensions of the field.


Equation: P = 2*L + 2*W ----> 2*(W + 18) + 2*W ----> 2*w + 36 + 2*W


          P = 4*W + 36 = 276 ----> 4*W = 276 - 36 ----> W = 240 / 4 = 60m

                                                        W = 60 m


          L = W + 18 = 60 + 18 = 78m


Therefore the dimensions of the field are: W = 60 m  and L = 78 m