Question 630850
y varies jointly as a and b, and inversely as the square root of c. 
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y = ka*b/sqrt(c)
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Find "k" if "y=140 when a=10, b=7 and c=36."
140 = k*10*7/sqrt(36)
140 = 70k/6
k = 12
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Equation:
y = 12*ab/sqrt(c)
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Find y when a=7, b=4, and c=16.
y = 12*7*4/sqrt(16)
y = 84
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Cheers,
Stan H.