Question 630760
 I need to dilute a 16 ounce bottle of 35 percent hydrogen peroxide
 to equal 12 percent hydrogen peroxide. How much water do I add?
:
Let w = amt of water required
A typical mixture equation
:
.35(16) = .12(w+16)
5.6 = .12w + 1.92
5.6 - 1.92 = .12w
3.68 = .12w
w = 3.68/.12
w = 30{{{2/3}}} oz needs to be added to reduce to a 12% mixtures 
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