Question 630713
Use the eccentricity of the ellipse to find the equation in the standard form. From the information, Foci (0,-3), (0,3) with eccentricity 1/9
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This is an ellipse with a vertical major axis
Its standard form of equation: (x-h)^2/b^2+(y-k)^2/a^2=1, a>b, (h,k)=(x,y) coordinates of center
For given ellipse;
center:(0,0)
Foci:
c=3
c^2=9
Eccentricity=c/a=1/9
a=9c=27
a^2=27^2=729
c^2=a^2-b^2
b^2=a^2-c^2=729-9=720
equation:
{{{x^2/720+y^2/729=1}}}