Question 630612
First lets find out how many y's are in an x. So if we subtract 6x and 6y from each side of the equation 6x+8y=7x+6y, we get 2y=x. So if we put 2y in for every x in 6x+8y=60, then we get 12y+8y=60, which is the same as 20y=60. So if we divide that by 20, we get y=3. So if we put y=3 into any equation, suppose 7x+6y=60, which is the same as 7x+18=60, and then we subtract 18 from each side, and then divide by 7,
7x=42
x=6
we get x=6. So y=3 and x=6.