Question 58030
If you put your equations into the slope-intercept form (y = mx+b) they are easier to graph.
x-2y = 8  Add 2y to both sides.
x = 2y+8  Subtract 8 from both sides.
x-8 = 2y  Finally, divide both sides by 2.
(1/2)x-4 = y or y = (1/2)x - 4
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3x-2y = 12 Add 2y to both sides.
3x = 2y+12  Subtract 12 from both sides.
3x-12 = 2y Finally, divide both sides by 2.
(3/2)x - 6 = y or y = (3/2)x - 6
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The graphs are:
{{{graph(300,200,-5,10,-8,5,(1/2)x-4,(3/2)x-6)}}}

From the graph, the solution (intersection) is at the point (2, -3).