Question 630485
Solve for x: 8e^(x)÷(e^(x)+3)=4 
How do I solve for x?
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{{{8e^x/(e^x+3)=4}}}
8e^x=4e^x+12
4e^x=12
e^x=3
xlne=ln12
lne=1 (log of base=1)
x=ln12
x≈2.48