Question 630341
carlos maneuvered his way through the first 80 miles in 5 hours.then he doubled his speed for the last part of the trip.if the total trip was 400 miles,how many hours did it take carlos to maneuver the last part?
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1st Part DATA:
distance = 80 miles ; time = 5 hrs ; rate = 80/5 = 16 mph
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2nd Part DATA:
distance = 400-80 = 320 miles ; rate = 2*16 = 32 mph 
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Equation:
2nd Part time = distance/rate = 320/32 = 10 hrs
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Cheers,
Stan H.
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