Question 630180
Given
Point (x, y)=(1,7) 
Line:
y=-x+5

Compare above equation with the equation of line slope-intercept form
y=mx+b
y=(-1)x+5

m=-1 and b=5
Slope of the given line m = -1 and y-intercept = b = 5

Since given line is parallel to the required line; slopes of the both line will be same.
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Now we have a point (1,7) and slope (-1) of the required line we can easily find the required line put these values in the equation of slope-intercept form to find the y-intercept of the required line
y=mx+b
7=(-1)(1)+b
7=-1+b
7+1=b
8=b
b=8
y-intercept of the required line =b=8
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Put the values of ‘m’ and ‘b’ in equation of the line slope-intercept form
y=mx+b
y=-1x+8
y=-x+8
x+y=8
Above equation is the required equation of the line in Standard form.



Graph
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y=-x+5 (Red line)
y=-x+8 (Green line)
{{{ graph(500,500,-10,10,-10,10,-x+5,-x+8) }}}