Question 630095
if log(2)3 = a and log(2)7 = b, 
express the following in terms of a & b. 
log(8)72 = log2(72)/log(2)8 = [log2(8)+log2(9)]/log2(8) 
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= 1 + [log2(9)/log2(8)]
==
= 1 + [2log2(3)/3]
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= 1 + (2/3)a
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Cheers,
Stan H.