Question 630016
The area of the 10 unit polygon is.      {{{ (10*10*N)/(4*tan(180/N)) }}}. The area of the 6 unit polygon is {{{ (6*6*N)/(4*tan(180/N)) }}}.   {{{ Ratio_of_the_areas=((10*10*N)/(4*tan(180/N)))/((6*6*N)/(4*tan(180/N)))=100/36=2.77 }}}.   Let A be the area of the larger polygon then.   A/12=2.77.      A=12*2.77.       A=33.24