Question 630070
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F is almost right, and is the nearest thing to a correct answer.  What would make it correct would be the restriction that the two shadows, i.e. from the meterstick and the tree must be wholly contained in the slope.  That is to say that your calculations will be off somewhat if the shadow of the tree reaches beyond the base of the hill and extends onto the presumably horizontal surface of the valley beneath the hill.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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