Question 629636
(3^5x)(27^5x)=(3^48)(9^8x)


(3^5x)((3^3)^5x)=(3^48)((3^2)^8x)


(3^5x)(3^(15x))=(3^48)(3^(16x))


3^(5x+15x) = 3^(48+16x)


3^(20x) = 3^(48+16x)


Since the bases are equal, the exponents are equal. So


20x = 48+16x


20x - 16x = 48


4x = 48


x = 48/4


x = <font color="red">12</font>


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