Question 629608
Use the quadratic formula to solve x^2-3x=-6
Re-write:
x^2 - 3x + 6 = 0
a = 1 ; b = -3 ; c = 6
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Formula: x = [-b +- sqrt(b^2-4ac)]/(2a)
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x = [3 +- sqrt(9-4*1*6)]/(2)
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x = [3 +- sqrt(-15)]/2
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x = (3/2)+(1/2)sqrt(15)i or (3/2)-(1/2)sqrt(15)i

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Cheers,
Stan H.
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