Question 57941
CIRCUMFERANCE OF THE BASE=2PIR THUS
C=2PI4
C=2*PI*4
C=8PI 
THE AREA OF THE TOP IS A=PIR^2
A=PI*4^2
A=PI*16 OR A=16PI AND THERE ARE 2 CIRCULAR AREAS (TOP & BOTTOM) THUS
2*PI*16=32PI 
THE CYLINDER SIDE AREA IS 8P1*HEIGHT
THUS THE TOTAL SURFACE AREA BEING 104PI=32PI+8PI*H
104PI-32PI=8PI*H
72PI=8PI*H
H=72PI/8PI
H=9 METERS