Question 629318
Solve the given equation cos2theta= 3sintheta-1
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cos(2t) = 3sin(t) - 1
1 - 2sin^2(t) = 3sin(t) - 1
2sin^2(t) + 3sin(t) - 2 = 0
Sub x for sin(t)
{{{2x^2 + 3x - 2 = 0}}}
x = -3/4 ± 5/4
x = -2
No real number solution
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x = 1/2
sin(t) = 1/2
theta = pi/6 + 2n*pi, n = 0,1,2,3...
theta = 5pi/6 + 2n*pi, n = 0,1,2,3...