Question 629298
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Hi
quadratic polynomial whose graph goes through the points (-1,5), (0,5), and (2,29). 
f(x) = ax^2 + bx + c
f(0) = 5 = c
f(x) = ax^2 + bx + 5   ****
a(-1)^2 + b(-1) + 5 = 5   ||  using (-1,5)
a*2^2  + 2b + 5 = 29      ||  using (2,29)
 a - b = 0
4a +2b = 24    ||multiplying 1st EQ thru by 2 and adding it to the second
  6a = 24
   a = 4  and b = 4   {{{a-b = 0}}}
 f(x) = 4x^2 + 4x + 5