Question 629290
How do you solve the following inequality? 
2+3(m+5)≥ 4(m+3) 
2+3m+15≥4m+12
3m-4m≥-17+12
-m≥-5
divide by -1 and reverse inequality sign
m≤5
solution: {m|m≤5}
or (-∞,5] (interval notation)