Question 629257
If {{{ n }}} is the 1st odd integer, then the 4 integers are
{{{ n }}}, {{{ n + 2 }}}, {{{ n + 4 }}}, and {{{ n + 6 }}}
given:
{{{ 5*( n + n + 4 ) = 4*( n + 2 + n + 6 )  + 14 }}}
{{{ 5*( 2n + 4 ) = 4*( 2n + 8 ) + 14 }}}
{{{ 10n + 20 = 8n + 32 + 14 }}}
{{{ 10n - 8n = 32 + 14 - 20 }}}
{{{ 2n = 26 }}}
{{{ n = 13 }}}
{{{ n + 2 = 15 }}}
{{{ n + 4 = 17 }}}
{{{ n + 6 = 19 }}}
The 4 integers are 13, 15, 17, and 19