Question 629225
b=3j
j=r+6
r=j-6

b+j+r=44

now you have three equations with three unknowns.
let's substitute and put in only j's
r=j-6

3j+j-6+j=44

5j-6=44
5j=50
j=10
b=3*10=30
r=10-6=4