Question 629164
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Hi,
In General {{{A = P(1+r/n)^(nt)}}}
A = Accumulated Amount $2000
P= principal = $1000
r= annual rate = .06
n= periods per year = 1
t= years =
 {{{2000 = 1000(1.06)^(t)}}}
  log 2/log(1.06) = t