Question 629070
what is the length of the transverse axis of the hyperbola defined by 
(x-5)^2/8^2-(y+3)^2/3^2=1
This is an equation of a hyperbola with horizontal transverse axis.
Its standard form: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}
given equation: 
{{{(x-5)^2/8^2-(y+3)^2/3^2=1}}}
={{{(x-5)^2/64-(y+3)^2/9=1}}}
a^2=64
a=8
length of horizontal transverse axis=2a=16