Question 629106
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-19,-10\right)]. So this means that {{{x[1]=-19}}} and {{{y[1]=-10}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-20,-15\right)].  So this means that {{{x[2]=-20}}} and {{{y[2]=-15}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-15--10)/(-20--19)}}} Plug in {{{y[2]=-15}}}, {{{y[1]=-10}}}, {{{x[2]=-20}}}, and {{{x[1]=-19}}}



{{{m=(-5)/(-20--19)}}} Subtract {{{-10}}} from {{{-15}}} to get {{{-5}}}



{{{m=(-5)/(-1)}}} Subtract {{{-19}}} from {{{-20}}} to get {{{-1}}}



{{{m=5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-19,-10\right)] and *[Tex \LARGE \left(-20,-15\right)] is {{{m=5}}}


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