Question 629078
{{{x^2+6x+y^2-2y=2}}}
{{{x^2+6x+3^2+y^2-2y + 1=2+ 3^2+1}}}
{{{(x+3)^2 + (y-1)^2 = (sqrt(12))^2}}} 

=> is a standard form {{{(x-a)^2 + (y-b)^2 = r^2}}}

center=(-3, 1)
radius = {{{sqrt(12)}}}