Question 629067


{{{(3x+2)(3x-5)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3x)+2)(highlight(3x)-5)}}} Multiply the <font color="red">F</font>irst terms:{{{(3*x)*(3*x)=9*x^2}}}.



{{{(highlight(3x)+2)(3x+highlight(-5))}}} Multiply the <font color="red">O</font>uter terms:{{{(3*x)*(-5)=-15*x}}}.



{{{(3x+highlight(2))(highlight(3x)-5)}}} Multiply the <font color="red">I</font>nner terms:{{{(2)*(3*x)=6*x}}}.



{{{(3x+highlight(2))(3x+highlight(-5))}}} Multiply the <font color="red">L</font>ast terms:{{{(2)*(-5)=-10}}}.



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So we have the terms: {{{9*x^2}}}, {{{-15*x}}}, {{{6*x}}}, {{{-10}}} 



{{{9*x^2-15*x+6*x-10}}} Now add every term listed above to make a single expression.



{{{9x^2-9x-10}}} Now combine like terms.



So {{{(3x+2)(3x-5)}}} FOILs to {{{9x^2-9x-10}}}.



In other words, {{{(3x+2)(3x-5)=9x^2-9x-10}}}.


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