Question 629066


{{{(4w^2-5)(w+5)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(4w^2)-5)(highlight(w)+5)}}} Multiply the <font color="red">F</font>irst terms:{{{(4*w^2)*(w)=4*w^3}}}.



{{{(highlight(4w^2)-5)(w+highlight(5))}}} Multiply the <font color="red">O</font>uter terms:{{{(4*w^2)*(5)=20*w^2}}}.



{{{(4w^2+highlight(-5))(highlight(w)+5)}}} Multiply the <font color="red">I</font>nner terms:{{{(-5)*(w)=-5*w}}}.



{{{(4w^2+highlight(-5))(w+highlight(5))}}} Multiply the <font color="red">L</font>ast terms:{{{(-5)*(5)=-25}}}.



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So we have the terms: {{{4*w^3}}}, {{{20*w^2}}}, {{{-5*w}}}, {{{-25}}} 



{{{4*w^3+20*w^2-5*w-25}}} Now add every term listed above to make a single expression.



{{{4w^3+20w^2-5w-25}}} Now combine like terms.



So {{{(4w^2-5)(w+5)}}} FOILs to {{{4w^3+20w^2-5w-25}}}.



In other words, {{{(4w^2-5)(w+5)=4w^3+20w^2-5w-25}}}.


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