<PRE><B>Question 629058</B>
If log(base 5)2 = m , express log 20 in terms of m.
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{{{log(5,2) = m}}}
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If you mean {{{log(10,20)}}}
then,
{{{log(5,2) = m}}}
20 = 2*5*2
log(20) = log(2) + log(5) + log(2) to any base
{{{log(5,20) = m + 1 + m = 2m+1}}}
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{{{log(5,10) = log(2) + log(5) = m+1}}}
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Use base change:
{{{log(10,20) = log(5,20)/log(5,10)}}}
= (2m+1)/(m+1)
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