<PRE><B>Question 629040</B>
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Two sides and the diagonal of a rectangle form a right triangle.  Solve the triangle using Pythagoras.  The diagonal is the hypotenuse of the triangle and the width is one of the legs.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ \sqrt{c^2\ -\ b^2}]


Just plug in the numbers and do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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