Question 628983
Side Note: this is NOT a slope equation.


I'll do the first part to start you off


The idea is to plug in the given number and evaluate


a)

{{{f(x)=x^2+3x-2}}}


{{{f(-2)=(-2)^2+3(-2)-2}}} Replace 'x' with -2


{{{f(-2)=4+3(-2)-2}}}


{{{f(-2)=4-6-2}}}


{{{f(-2)=-4}}}


So the answer to part a) is {{{f(-2)=-4}}}


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