Question 628905
Alloy-A
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Amount = 40 ounces
Concentration = 35%=0.35



Alloy-B
========
Amount = 62 ounces
Concentration = 20%=0.20


Resultant Alloy
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Amount = Alloy-A + Alloy-B = 40+62 = 102 ounces
Concentration = x




(Amount of Alloy-A)(Concentration of Alloy-A)+(Amount of Alloy-B)(Concentration of Alloy-B)= (Amount of Resultant Alloy)(Concentration of Resultant Alloy)
(40)(0.35)+(62)(0.20)= (102)(x)
14+12.4=102x
26.40=102x
102x=26.04
102x/102=26.04/102
x=0.2588

Concentration of the resultant alloy will be approximately 0.2588 or approximately 26%.