Question 628737
Find the exact solution:

log(x+3)=1-log(x)


log (x + 3) = 1 – log x
log (x + 3) + log x = 1 
log x(x + 3) = 1


{{{10^1 = x(x + 3)}}}


{{{x^2 + 3x - 10 = 0}}}


(x + 5)(x – 2) = 0


x = - 5 (ignore), or {{{highlight_green(x = 2)}}} (accept)


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Check
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log (2 + 3) = 1 – log 2
log 5 = 1 – log 2
0.69897 = 1 - 0.30103
0.69897 = 0.69897 (TRUE) 


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