Question 628741
Let the first odd integer be 2n+1. The next three consecutive odd integers are 2n+3, 2n+5 and 2n+7. So 2n+1+2n+3+2n+5+2n+7=56.    8n+16=56.    8n=40.   n=5.  So the first odd integer is 2*5+1.    11.