Question 628629

Two trains start from P and Q respectively and travel towards each other at a speed of 50 km/hr and 40 km/hr respectively. By the time they meet, the first train has traveled 100 km more than the second. Find the distance between P and Q.

Need answer with solution urgently.. Thanks a million..


Let distance traveled by faster train be D
Then distance traveled by slower train = D - 100
Time taken by faster train to travel to meeting point = time taken by slower train to travel to the meeting point, OR
{{{D/50 = (D - 100)/40}}}


50(D – 100) = 40D ------ Cross-multiplying


50D – 5,000 = 40D


50D - 40D = 5,000


10D = 5,000
D, or distance traveled by faster train = {{{5000/10}}}, or {{{500}}} km


Distance traveled by slower train = 500 – 100, or {{{400}}} km


Therefore, distance between P and Q = 500 + 400, or {{{highlight_green(900)}}} km


You can do the check, I'm sure!!


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