Question 628607
solve:
{{{3/(x+3)}}} - {{{1/(x^2-9)}}} = {{{1/(x-3)}}}
the 2nd denominator is the difference of square and will factor:
{{{3/(x+3)}}} - {{{1/((x-3)(x+3))}}} = {{{1/(x-3)}}}
Multiply thru by (x-3)(x+3) and you have
3(x-3) - 1 = x + 3
multiply what's inside the brackets
3x - 9 - 1 = x + 3
3x - 10 = x + 3
3x - x = 3 + 10
2x = 13
x = 6.5