Question 628520
What is the measures of two complementary angles such that the larger angle is six less than twice the smaller angle?
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let x=larger of two complementary angles
90-x=smaller of two complementary angles
..
x=2(90-x)-6
x=180-2x-6
3x=174
x=58
90-x=32
larger of two complementary angles=58º
smaller of two complementary angles=32º