Question 628492


{{{(3p^2-p)(3p^2-p)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(3p^2)-p)(highlight(3p^2)-p)}}} Multiply the <font color="red">F</font>irst terms:{{{(3*p^2)*(3*p^2)=9*p^4}}}.



{{{(highlight(3p^2)-p)(3p^2+highlight(-p))}}} Multiply the <font color="red">O</font>uter terms:{{{(3*p^2)*(-p)=-3*p^3}}}.



{{{(3p^2+highlight(-p))(highlight(3p^2)-p)}}} Multiply the <font color="red">I</font>nner terms:{{{(-p)*(3*p^2)=-3*p^3}}}.



{{{(3p^2+highlight(-p))(3p^2+highlight(-p))}}} Multiply the <font color="red">L</font>ast terms:{{{(-p)*(-p)=p^2}}}.



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So we have the terms: {{{9*p^4}}}, {{{-3*p^3}}}, {{{-3*p^3}}}, {{{p^2}}} 



{{{9*p^4-3*p^3-3*p^3+p^2}}} Now add every term listed above to make a single expression.



{{{9p^4-6p^3+p^2}}} Now combine like terms.



So {{{(3p^2-p)(3p^2-p)}}} FOILs to {{{9p^4-6p^3+p^2}}}.



In other words, {{{(3p^2-p)(3p^2-p)=9p^4-6p^3+p^2}}}.


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