Question 628458
The equation 10x - 6y = -11 in slope intercept form is {{{y = (5/3)x + 11/6}}}.
The slope of the line perpendicular to  {{{y = (5/3)x + 11/6}}} is equal to the negative reciprocal of {{{5/3}}} which is {{{-3/5}}}.
We want to find the equation of the line with slope {{{-3/5}}} and containing the point (-5,-8).
{{{y - y[1] = m(x - x[1])}}}
{{{y + 8 = (-3/5)(x + 5)}}}
{{{highlight(y = (-3/5)x - 11)}}}