Question 57906
Rules of exponents we will use:
{{{highlight((a^m)(a^n)=a^(m+n))}}}
{{{highlight(a^(-m)=1/a^m)}}}
{{{highlight(1/a^(-m)=a^m)}}}
:
{{{x^2y^-3z^-5/(x^-4y^3)}}}  It's easiest for me to take care of the negative exponents first.
{{{x^2x^4/y^3y^3z^5}}}
{{{x^(2+4)/(y^(3+3)z^5)}}}
{{{highlight(x^6/(y^6z^5))}}}
Happy Calculating!!!