Question 628351
Let the consecutive integers = {{{ n }}} and {{{ n + 1 }}}
given:
{{{ 3n + 4*( n + 1 ) = 137 }}}
{{{ 3n + 4n + 4 = 137 }}}
{{{ 7n = 133 }}}
{{{ n = 19 }}}
{{{ n + 1 = 20 }}}
The integers are 19 and 20