Question 628258
If a satellite is orbiting earth, it’s distance from the center of earth is dependent upon it’s orbital velocity (speed at which it orbits the earth). The distance, r, that the satellite is from the center of the earth can be found using this equation: r=Kv^-2 , where K is a constant and v is the satellite’s orbital velocity. 
1. Solve the equation for v. (Remember to use the negative exponent rule to write the expression with positive exponents before solving for v)
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Don't tell us what to remember.  If we didn't know how to do, we wouldn't be here.
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{{{r=Kv^-2}}}
Multiply by v^2
{{{rv^2=K}}}
Divide by r
{{{v^2 = K/r}}}
{{{V = sqrt(K/r)}}}
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2. Suppose that a satellite orbiting at a velocity of 4.93 km/s has an altitude such that the distance from the center of the earth to the satellite is 16378 km. Find the value of K that makes the equation true.
{{{rv^2=K}}}
{{{K = 16378*4.93^2}}}
K =~ 398065.65
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3. Use the value of K you found in the previous problem to determine the altitude of a satellite orbiting at a velocity of 5.4 km/s
Note: The altitude of the satellite is its height above the surface of the earth. The radius (distance from the center to the surface) of the earth is 6378 km, you will need this number to find the altitude of the satellite once you have found a value for r.
{{{r=Kv^-2}}}
It's just calculator work.
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4. Find the orbital velocity of a satellite with an altitude of 15,000 km above the surface of the earth. 
Use a calculator, plug in the numbers given.