Question 627566
Hello! I need help solving 2 equations involving Logarithms. 
How do I correctly graph the equation bellow on the same coordinate plane.
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Question #1: F(x)= 2^-x and G(x)= 4^x
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For F(x)=2^-x=1/2^x
Domain: (-∞,∞)
Range: (0,∞)
Horizontal asymptote: x-axis or y=0
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For F(x)=4^x
Domain: (-∞,∞)
Range: (0,∞)
Horizontal asymptote: x-axis or y=0

See graph below: Green curve is 4^x and red curve is 2^-x or 1/2^x
Note that both curves have a y-intercept=1 (2^0=1)
Also note both functions are always >0
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Question #2: 
How do I solve/or rewrite this equation as a single quantity? 
log^2 (x) + log^2 (x+2) = log^2 (x +6)
log^2[ (x) (x+2)] = log^2 (x +6)
x(x+2)=x+6
x^2+2x=x+6
x^2+x-6=0
(x+3)(x-2)=0
x=-3 (reject, x>0)
or
x=2

{{{ graph( 300, 300, -10, 10, -10, 10,1/2^x,4^x) }}}