Question 628165
You can think of this as one truck standing still
and the other traveling away at the sum of their speeds
Let the speed of the slower truck = {{{ s }}} mi/hr
Let the speed of the faster truck = {{{ s + 3 }}} mi/hr
The equation for the moving truck is
{{{ 206 = (s + s + 3 )*2 }}}
{{{ 206 = 4s + 6 }}}
{{{ 4s = 200 }}}
{{{ s = 50 }}}
{{{ s + 3 = 53 }}}
The speeds of the trucks are 50 and 53 mi/hr