Question 628092
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Hi,
I. find Mean and SD for each sample. 
Sample 1: m = 589, SD = 42.615
Sample 2: m = 684.9,  SD = 82.225
II.  Find the t-value
t ={{{( mean [2]- mean [1])/sqrt(SD [1]^2/n[1] + SD[2]^2/n[2])= 3.2745}}}
Which is significant at the 99% Level(degree of Freedom 18):  3.2745 > 2.88 				
DF	0.1	0.05	0.01	0.001
18	1.73	2.1	{{{highlight(2.88)}}}	3.92
b)What is the difference between the mean of the two groups? 684.9-589
What is the difference is standard deviation? 82.25-42.615
c)What is the null and alternative hypothesis? 
{{{H[o]}}}: m for over weight people &#8804; 589
{{{H[a]}}}: m for over weight people > 589 
As 3.2745 > 2.88, we reject the null hypothesis
overweight people do eat faster according to this study