Question 627989
what is the foci of this ellipse. 
x^2/64 + y^2 =1
This is an equation of an ellipse with horizontal major axis
center: (0,0)
a^2=64
a=√64=8
b^2=1
b=1
c^2=a^2-b^2=64-1=63
c=√63≈7.9
foci: (0±c,0)=(0±7.9,0)=(-7.9,0) and (7.9,0)