Question 57858
I'm having trouble interpretting your problems because I know where your radicals begin, but I don't know where they end.  If I misinterpret, let me know and I'll change it.
{{{sqrt(x+4)=3}}}
{{{(sqrt(x+4))^2=(3)^2}}}
{{{x+4=9}}}
{{{x+4-4=9-4}}}
{{{x=5}}}
Check your answers everytime that you do square root problems for extraneous soltuions:
{{{sqrt(5+4)=3}}}
{{{sqrt(9)=3}}}
{{{3=3}}}  Our solution is fine, x=5
Happy Calculating!!!