Question 57864
Write the equation of the line that passes through the given point and is parallel to the given line.  Write the answer in slope-intercept form

P(-6,3), y + 3x = -12

The first thing you need to do is find the slope of the line they gave you.  Parallel lines have equal slopes.
Once we know a point and a slope we can writhe the equation of the line using the point-slope fomrula.
:
To find the slope of an equation of a line, put the equation in slope-intercept form:  {{{highlight(y=mx+b)}}}, where slope=m, and y-intercept=(0,b).
:
y+3x=-12
y+3x-3x=-3x-12
{{{y=highlight(-3)x-12}}}  The slope is m=-3
:
The point-slope formula is: {{{highlight(y-y1=m(x-x1))}}}
P(-6,3) tells us x1=-6 and y1=3.  We just found m=-3.  So plug and chug:
{{{y-(3)=-3(x-(-6))}}}
{{{y-3=-3(x+6)}}}
{{{y-3=-3x-18}}}
{{{y-3+3=-3x-18+3}}}
{{{highlight(y=-3x-15)}}}
Happy Calculating!!!